Charts

What you CAN'T get (see below for white):
If BOTH parents are:		you can't get:
black	K(K/k^br/k) x K(K/k^br/k)	fawns & brindles in the same litter because each parent can only carry 1 other gene at the K locus they can only produce one other color besides black.
blue (solid, fawn, or brindle)	dd x dd	black pigment or coat because there is no dominant D gene 2 blues cannot produce black pigment or coat color
brindle	a^ya^yk^br(k^br/k) x ayayk^br(k^br/k)	solid blacks or blues because there is no dominant K gene 2 brindles cannot produce solid blacks or blues
fawn	a^ya^yE^m(E^m/E/e)kk x a^ya^yE^m(E^m/E/e)kk	brindle because there is no brindle (k^br) gene 2 fawns cannot produce brindles
fawn	a^ya^yE^m(E^m/E/e)kk x a^ya^yE^m(E^m/E/e)kk	solid black or solid blue (*see Note below) because there is no dominant K gene 2 fawns cannot produce solid blacks or blues
If parents are:		you can't get:
brindle x fawn	a^ya^yk^br(k^br/k⁾ x a^ya^ykk	solid blacks or blues because there is no dominant K gene a fawn and brindle cannot produce solid blacks or blues
*Note: EXCEPT if one parent has absolutely NO black hairs then that dog might be a fawn produced by the double "ee" recessive and such a fawn CAN produce a solid black or blue (if the dog is a genetic black or blue) when bred to a normal fawn

White - what you CAN"T get: NOTE: in white markings the action of plus (+) and minus (-) modifiers cause some overlap of visible markings, so take these as generalizations - not absolutes!
If BOTH parents are:		you can't get:
solid	S(sⁱ/s^p/s^w) x S(sⁱ/s^p/s^w)	solids & Irish marked & parti-color & extreme white because there are 4 genes at the S locus, these 2 parents cannot produce all 4 patterns
Irish marked	sⁱ(sⁱ/s^p/s^w) x sⁱ(sⁱ/s^p/s^w)	solids, or Irish marked & parti-color & extreme white because there are 2 other genes recessive to Irish marked, 2 parents cannot produce all 3 patterns. Solids are excluded by the absence of the dominant Solid gene
Parti-color	s^p(s^p/s^w) x s^p(s^p/s^w)	solids or Irish marked Solids and Irish marked are excluded by the absence of the genes for these patterns
Extreme White	s^ws^w x s^ws^w	solids, or Irish marked, or parti-color Solids and both Irish marked and parti-color are excluded by the absence of the genes for these patterns
If parents are:		you can't get:
solid x Irish marked	S(sⁱ/s^p/s^w) x sⁱ(sⁱ/s^p/s^w)	Irish marked & parti-color & extreme white because there are 3 white-pattern genes at the S locus, these 2 parents cannot produce all 3 patterns in one litter
solid x parti-color	S(sⁱ/s^p/s^w) x s^p(s^p/s^w)	Irish marked & parti-color & extreme white Because there are 3 other genes at this locus, these 2 parents cannot produce all 3 patterns in one litter
solid x extreme white	S(sⁱ/s^p/s^w) x s^ws^w	Irish marked & parti-color & extreme white because there are 3 other genes at this locus these 2 parents cannot produce all 3 patterns in one litter
Irish marked x parti-color	sⁱ(sⁱ/s^p/s^w) x s^p(s^p/s^w)	solids, or parti-color & extreme white solids are excluded by the absence of the solid gene. Because there are 3 other genes at this locus, these 2 parents cannot produce all 3 patterns in one litter
Irish marked x extreme white	sⁱ(sⁱ/s^p/s^w) x s^ws^w	solids, or parti-color & extreme white solids are excluded by the absence of the solid gene. Because there are 3 other genes at this locus, these 2 parents cannot produce all 3 patterns in one litter
parti-color x extreme white	s^p(s^p/s^w) x s^ws^w	solids or Irish marked solids are excluded by the absence of the solid gene. Irish marked is excluded by the absence of the gene for this pattern.

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